In The Game Of Roulette A Player Can Place

In The Game Of Roulette A Player Can Place

Solution for in the game of roulette, a player can place a $4 bet on the number 33 and have a 138 probability of winning. If the metal ball lands on 33, the. 1.In the game of roulette, a player can place a $6bet on the number 10and have a StartFraction 1 Over 38 EndFractionprobability of winning. Worlds best dice games. If the metal ball lands on 10,the player gets to keep the $6paid to play the game and the player is awarded an additional $210. In the game of roulette, a player can place a $9 bet on the number 5 and have a 1/38 probability of winning. If the metal ball lands on 5, the player gets to keep the $9 paid to play the game,. In the game of roulette, a player can place a $4 bet on the number 22 and have a 1/38 probability of winning. If the metal ball lands on 22, the player gets to keep the $4 paid to play the game and the player is awarded $140. Otherwise, the player is awarded nothing and the casino takes the players. In the game of roulette, a player can place a $6 bet on the number 10 and have a 1 / 38 probability of winning. Best vegas craps. If the metal ball lands on 10, the player gets to keep the $6paid to play the game.
In The Game Of Roulette A Player Can PlaceAlgebra -> Probability-and-statistics-> SOLUTION: in the game of roulette, a player can plave a 6$ bet on the number 21 and have a 1/38 probability of winning. If the metal ball lands on 21, the player gets to keep the 6$ paid to Log On

In The Game Of Roulette A Player Can Place A $7 Bet

In the game of roulette a player can place a $7 bet

In The Game Of Roulette A Player Can Place A
Question 530077:  in the game of roulette, a player can plave a 6$ bet on the number 21 and have a 1/38 probability of winning. If the metal ball lands on 21, the player gets to keep the 6$ paid to play the game and the player is awarded 210$ . otherwise the player is awarded nothing and the casino takes the players 6$. What is the expected vaule of the game to the player? If you played the game 1000 times, how much would you expect to lose? 
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
 in the game of roulette, a player can place a 6$ bet on the number 21 and have a 1/38 probability of winning. If the metal ball lands on 21, the player gets to keep the 6$ paid to play the game and the player is awarded 210$ . otherwise the player is awarded nothing and the casino takes the players 6$. What is the expected value of the game to the player?
E(x) = 210(1/38) + (-6)37/38) = (210-222)/38 = -12/38 = -$0.3158
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If you played the game 1000 times, how much would you expect to lose?
Ans: 1000(-0.3158) = $315.80
cheers,
Stan H.

In The Game Of Roulette A Player Can Place A $10 Bet